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Wysłany: Śro 3:45, 08 Gru 2010 Temat postu: ugg milano Theoretical Study of alignment drill _2 |
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Theoretical Study of alignment drill
Radius: M: {[(lost a calyx) c a) +] (5a) 2Jj 'where: a ratio in diameter,[link widoczny dla zalogowanych], a = r / R, M is the elastic limit moment, M = 7rR. (1 a d) / 4, the plastic layer depth,: / h = R / R. (2) there are small round plastic deformation, that is, r ≥ r ≥ 0, r is the elastic nuclear height, and r / r = / a, M: [(lost a Pi) (* a) {a (a2 lost a calyx) arcsin ~ \(5b) so that 7v ~ '/ = M / M, (6) plastic materials, plastic bending as the ideal ratio. For ease of calculation, the introduction of curvature. Let the original curvature k. , Anti-bending rate k, playing complex curvature k, the residue of rebound after the curvature k,, the total bending curvature k,, plastic deformation curvature k,[link widoczny dla zalogowanych],. And requiring the person is positive curvature concave, convex, who is negative. Alignment in the general case, the original curve is convex, that is negative. Which was the relationship between the curvature shown in Figure 2. k, = k a (first 0) = kI-k0, (7a) k = k a k, (7b) kr = k a (first 0) = kI-k0. (7c) that Ms | El: ks,. 118. Harbin Engineering University Vol 23 curvature diagram in Figure 2 Fig. 2Curvaturesrdationk called the elastic limit curvature, which, for the bending section modulus,, = (R A r) / 4. Alignment to make the part is to be made the residual curvature k,[link widoczny dla zalogowanych], = 0, even if the rate of anti-bend curvature of rebound equal to: k = k. Law based on a simple uninstall know: ke = M | El = Msm / EI, according to equation (6) can be obtained: k:. ( According to equation (2), (4) have: e = / p and e: hk, and = h / h. So come kt / k = h / h = 1, the Stone = 1 (Note: Stone = kw / k, as the relative rate of anti-bend, stone, stone, stone., Stone, empathy, and relationship with the type (7) the same.) The relationship between the generation type (5) may: (1) 1 ≥ Chi, ≥ a, the stone = {[(lost first-class) +2 k BU kjl '(2) a ≥ Chi,> 0, = [ ,],[(9b), and k = k + k0. (9c) according to equation (9) relationship, in a given stone. Value of the stone can be obtained after the value, so you can come. And the numerical relationship between the stone. Curved alignment as the anti-missile complex curvature and curvature are equal, ie == M / Ej, so anti-deflection curve is also equal to the reduction of the deflection of rebound (see Figure 1), that is, = e = M1/3EI. Comprehensive two equations, the reverse bending deflection can be expressed as = z final blog / 3 = z blog is / 3, (10) should put pressure on pressure points for the F = 2Ml /. (11) for the circular cross-section: l ≤ Ⅲ ≤ (1.27 ~ 1.69), folded into deflection ≤ ≤ (1.27 ~ 1.69), where = zk / 3, called the elastic limit deflection. 3 Calculation of the hole straightening force complicated, frequent bending over curvature, so the use of straightening the curved section of each approach to operations. According to the theory of computation can be drawn diagram of alignment. First, the alignment should be measured in various parts of the initial deflection of curved segments, the maximum deflection of the curved section of selected deformation curve fitting to calculate the initial curvature k. Secondly,[link widoczny dla zalogowanych], part of the maximum deflection at or near the maximum deflection at the pressure point, as far as possible the distribution of symmetry in the two pressure points as the fulcrum of the pressure, the fulcrum from the original by the section size and curvature to be. Third, in determining the pressure point k, the calculation of the stone, from (6), (, (9) by Stone and M. And then by type (1O) get by (11) by F, pressure point reduction amount = +, ¨ the fourth, according to the amount of pressure and pressure control of press work. After the first round of alignment, and then repeat the first steps, so you can be part of each arc on the alignment. Figure 3 shows the calculation diagram. Diagram calculated according to the school straight to X95 drill as an example: the minimum yield strength = 723.24MPa, ID 121.36ml 'n, thickness 9.17ml' n, Young's modulus E = 210GPa,[link widoczny dla zalogowanych], length L = 101TI, fulcrum distance 2z = 1.51TI, pressure point between the fulcrum. The results shown in Figure 4, Figure 5 and Table 1 below: Table 1, the initial deflection and anti-bending deflection, alignment, and stress reduction numerical relationship between the amount of Table1Mathematicalvaluerelationof0, Sunburn. , AndF 3 Figure 3 Bo Yu a plastic mechanics [M]. Beijing: Science Press, I99. Calculation diagram of straightening black ingca / cu / ation woman. A chart of a foot [Editor: Li Ling Chu]
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